The amount of heat supplied to 0.02 kg of nitrogen to raise its temperature by 45˚ is:
Correct answer: B. 934J
- A. 935J
- B. 934J
- C. 967J
- D. 954J
Explanation
Mass of nitrogen, m = 0.02 kg = 2×10-2×103Rise in temperature, ΔT=45oCMolecular mass of N2 ,M=28Universal gas constant, R=8.3J/molKNumber of moles, n= m/M=(2×10-2×103) / 28=0.714Molar specific heat at constant pressure for nitrogen, Cp = (7/2)R=(7/2)×8.3=29.05 Jmol-1 K-1 The total amount of heat to be supplied is given by the relation: Q=nCp ΔT=0.714×29.05×45=933.38JTherefore, the amount of heat to be supplied is 933.38 J.This is numerical so it can only have one answer so option B is correct.
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About Molar Specific Heat of a Gas
Molar specific heat is the heat required to raise the temperature of one mole of a gas by one kelvin, expressed through Q = nCΔT. Questions compare the constant volume value Cv with the constant pressure value Cp, apply the ideal gas relation Cp − Cv = R, and identify how the thermodynamic process affects heat capacity.
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