The amount (in liters) of oxygen at STP that is required for the combustion of 4g of ethylene is:
Correct answer: B. 9.6 liters
- A. 96 liters
- B. 9.6 liters
- C. 44.8 liters
- D. 7.2 liters
Explanation
The balanced equation for this reaction will be C2H4 + 3O2 → 2CO2 + 2H2O Moles of ethylene given: moles= mass/Mr = 4/28 =1/7 moles Molar Ratio of ethylene and oxygen: C2H4 : O2 1 : 3 1/7 : x (mole of oxygen at stp) x=3/7 moles=volume/22.4dm3 3/7=v/22.4 v=9.6 Litres
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The mole connects the microscopic number of particles with measurable mass, using Avogadro's number, 6.022 × 10²³ particles per mole. Questions involve molar mass, conversion between mass, moles and particles, percentage composition, empirical and molecular formulas, and distinguishing atoms, molecules, ions and formula units.
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