The alveolar ventilation in an individual with tidal volume: 600 ml, dead space 150 ml and respiratory rate of 15/ minute is_____________?
Correct answer: D. 6.75 Lit/Min
- A. 2.5 lit/Min
- B. 4.0 lit /Min
- C. 9 Lit/Min
- D. 6.75 Lit/Min
Explanation
Alveolar ventilation equals (tidal volume − dead space) × respiratory rate. Thus, (600 − 150) × 15 = 6,750 ml/min, or 6.75 L/min.
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