The actual amount of CaO obtained on thermal decomposition of 25g of CaCO₃ is 12g. What is the approximate percentage yield? (Molar mass of CaCO₃ = 100, Molar mass of CaO = 56) CaCO₃ → CaO + CO₂

Correct answer: C. 86 %

  • A. 50 %
  • B. 60 %
  • C. 86 %
  • D. 90 %

Explanation

From the equation, 100 g of CaCO3 gives 56 g of CaO, so 25 g should give 14 g, which is the theoretical yield. The percentage yield is 12 divided by 14, multiplied by 100, which is about 86 percent. Dividing 12 by 25 instead gives 48 percent, close to the 50 percent distractor.

This question appeared on the UHS MDCAT 2026 paper, which you can sit online with every answer explained.

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About Theoretical and Percentage Yield

Theoretical yield is the maximum product predicted from a balanced equation and the amount of limiting reactant. Work includes identifying the limiting reagent, comparing theoretical and actual yield, and calculating percentage yield using stoichiometric mole relationships.

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