The acceleration of free fall on the Moon is one-six of that of Earth. On Earth, it takes time 't' for a stone to fall from rest a distance of 2 m. What is the time taken for a stone to fall from rest a distance of 2 m on the Moon?
Correct answer: C. t√6
- A. 6 t
- B. T/6
- C. t√6
- D. t/√2
Explanation
Let the acceleration of free fall on Earth = gAcceleration of free fall on Moon = g16The stone is released from rest at a height of 2m.Initial velocity, u = 0. Distance, s = 2mEquation for uniformly accelerated motion: s = ut + ½ at2On Earth, the time taken is t 2=0+0.5g12Acceleration,g=4/12Now, consider the stone falling on the Moon. Let the time taken be tM. 2=0+0.5 (g/6) tM2Time tM = √(4/9)=√(24/4/12)) = ✓(6/12)=⅙As it is a numerical, it can have only one possible answer.
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