Technitium-99 has a half-life of 6 hours. If there is 300 mg of it, how much will be left in 48 hours?
Correct answer: C. 1.17 mg
- A. 1.58 mg
- B. 1.25 mg
- C. 1.17 mg
- D. 2.56 mg
Explanation
Technetium-99 (Tc-99) has a half-life of 6 hours. You start with 300 mg of it.Amount left = Initial amount × (1/2)^(time / half-life)Amount left = 300 mg × (1/2)^(48 hours / 6 hours)Amount left = 300 mg × (1/2)^8Amount left ≈ 1.1719 mgSo, after 48 hours, approximately 1.1719 mg of Technetium-99m will remain from the initial 300 mg.
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