Strain energy in deformed energy is stored in the form of:

Correct answer: B. Potential Energy

  • A. Elastic Energy
  • B. Potential Energy
  • C. Plastic Energy
  • D. Kinetic Energy

Explanation

For an object that is deformed energy as stored as the potential energy and is known as the Strain energy.Elastic energy is the energy stored in a deformed object when it undergoes elastic deformation. This energy is stored in the form of potential energy within the object's molecular or atomic bonds.Potential energy is a type of energy associated with the position or configuration of an object. In the case of a deforming train, potential energy is stored as the train's shape changes. This potential energy can be released or converted into other forms of energy, such as kinetic energy, when the train returns to its original shape or undergoes further deformation.Plastic energy Is not a correct term.Kinetic energy is the energy of motion. While a deforming train may have some kinetic energy due to its motion.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? support@testustad.com

About Physics of Solids

Solids are compared through crystal structure, amorphous arrangement, elasticity, plastic deformation, stress, strain and Young’s modulus. Electrical behavior depends on available charge carriers and band structure, so conductors, insulators and semiconductors must be distinguished from mechanical properties such as strength, stiffness and brittleness.

Practise Physics of Solids

320 free Physics of Solids MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 11 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Physics of Solids questions