Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 ms-1, its frequency is:
Correct answer: C. 5 Hz
- A. 2 Hz
- B. 4 Hz
- C. 5 Hz
- D. 10 Hz
Explanation
(Remember that node to node is half A) so λ= 10/5 and then λ = 2x2=4mThen we find out the frequency using the formula v = fλ ie 20 = f(4) and f = 20/4 = 5 Hz As it is numerical, it can have only one possible answer.
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About Stationary Waves
Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.
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