Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 ms-1, its frequency is:
Correct answer: C. 5 Hz
- A. 2 Hz
- B. 4 Hz
- C. 5 Hz
- D. 10 Hz
Explanation
(Remember that node to node is half A) so λ= 10/5 and then λ = 2x2=4mThen we find out the frequency using the formula v = fλ ie 20 = f(4) and f = 20/4 = 5 Hz As it is numerical, it can have only one possible answer.
This question appeared on the ETEA MDCAT 2017 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Stationary Waves
Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.
Practise Waves
1,281 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Stationary Waves questions
Stationary waves are result of _ travelling in opposite direction waves.
A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is:
The number of loops in the standing waves is directly dependent on:
In stationary waves: