Self-fertilization of F1 dihybrids, following an independent assortment of alleles, will result in:

Explanation

Option D is correct.Yes, self-fertilization of Fr dihybrids, following an independent assortment of alleles will result in a phenotypic ratio of 3:16 tall, wrinkled: 3:16 dwarf, round. In a dihybrid cross, two genes are considered. In this case, the genes are for height (T=tall and t=dwarf) and seed shape (R=round and r=wrinkled). The dihybrids are heterozygous for both genes, meaning they have one allele for each trait from each parent. When the dihybrids are self-fertilized, the offspring will inherit one allele for each trait from each parent. The possible outcomes are TTRR: This offspring will be homozygous dominant for both traits. TTRr: This offspring will be heterozygous for height and homozygous dominant for seed shape. TTrr: This offspring will be heterozygous for height and heterozygous for seed shape. ttRR: This offspring will be homozygous dominant for height and heterozygous for seed shape. ttRr: This offspring will be heterozygous for height and heterozygous for seed shape. ttrr: This offspring will be homozygous recessive for both traits. The phenotypic ratio of the offspring will be 9:3:3:1, with 9 offspring showing the dominant phenotype for both traits, 3 offspring showing the dominant phenotype for height and the recessive phenotype for seed shape, 3 offspring showing the recessive phenotype for height and the dominant phenotype for seed shape, and 1 offspring showing the recessive phenotype for both traits. The genotype ratio of the offspring will be 1:2:2:1, with 1 offspring homozygous dominant for both traits, 2 offspring heterozygous for height and homozygous dominant for seed shape, 2 offspring heterozygous for height and heterozygous for seed shape, and 1 offspring homozygous recessive for both traits.