Resultant of two forces 30N and 40N acting perpendicular to each other is

Explanation

Of course, with a triangle with a 90° angle, a right triangle, you can simply use.Pythagoras theorem (a2+b2=c2) then SOH-CAH-TOA to solve for the angle (\theta=Cos-1(\frac{adjacent}{hypotenuse} )) .(θ=Cos−1(adjacent/hypotenuse)).But what if it isn't a right triangle? The cosine rule works for all triangles, even if they don't have a 90° angle.a2=b2+c2−2(b)(c)Cos(A)aWhere a is the missing side, and A is the angle opposite to side a.With this rule, we can find a missing angle or a missing side to any type of triangle, assuming you have the needed variables.Let's plug your example in:Let b=40 c=30 and A=90°a2=402+302-2(40)(30)Cos(90)a Cos(90)=0 which is why Pythagoras theorem works at 90°, but I'll continue as if it did matter.a2=2500-2(40)(30)Cos(90)a 2 =2500−2(40)(30)Cos(90)a2=2500-2400*0a2 =2500−2400∗0a=√{2500}a= 2500a=50Na=50N