Ratio of percentage of s and p in sp2 hybridization is:
Correct answer: A. s = 33.3%, p = 66.6%
- A. s = 33.3%, p = 66.6%
- B. p = 33.3%, s = 66.6%
- C. s = 40%, p = 60%
- D. s = 25%, p = 75%
Explanation
In sp2 hybridization, the ratio of the percentage of s and p character in the hybrid orbitals is approximately 1:2. When an atom undergoes sp2 hybridization, one s orbital combines with two p orbitals to form three sp2 hybrid orbitals. These hybrid orbitals have a different distribution of electron density compared to the original atomic orbitals. The percentage of s character in each sp2 hybrid orbital is about 33.33%, and the percentage of p character is about 66.67%. This ratio is roughly 1:2. It's important to note that this is an approximate ratio, and in more detailed calculations, the percentages may vary slightly, but the 1:2 ratio is a good simplification for understanding sp2 hybridization.
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