Radon 22286Rn decays by α -and β-emission to bismuth 83214Bi for the decay of each nucleus of radon. How many α-and β-particles are emitted?
Correct answer: B. B option
- A. A option
- B. B option
- C. C option
- D. D option
Explanation
No of α - particles = 2No of β - particles = 1 The equations can be written as:22286Rn → 21884X + alpha particle21884X → 21482Y + alpha particle21482Y → 21483Bi + 0-1e
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