Question 22: A boy holds a 40-N weight at arm's length for 10 seconds. His arm is 1.5m above the ground. The work done by the force of the boy on the weight while he is holding it is: (Work, Power & Energy, work done by constant and variable forces)

Correct answer: A. 0 j

  • A. 0 j
  • B. 90 j
  • C. 60 j
  • D. 40 j

Explanation

Correct Answer: (a) 0 J Explanation:Work (W) = F x dWhile the boy exerts force (40 N), the weight doesn't move any distance (d = 0), so W = 40 N x 0 m = 0 J.Incorrect Options:(b) 90 J: This option confuses potential energy gain (40 N x 1.5 m = 60 J) with work done, which requires actual displacement.(c) 60 J: Same mistake as (b) - calculating potential energy instead of work.(d) 40 J: Considers only the force applied, ignoring the lack of displacement needed for work to be done.

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About Work and Energy

Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.

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