Propanone on oxidation gives:
Correct answer: B. Formic acid + Acetic acid
- A. Acetic acid
- B. Formic acid + Acetic acid
- C. Formic acid
- D. Propionic acid
Explanation
The correct answer is B) Formic acid (HCOOH) and Acetic acid (CH3COOH). When propanone (acetone) is oxidized, it gives a mixture of formic acid and acetic acid as the products. The overall reaction can be represented as follows: CH3COCH3 + 2O2 → HCOOH + CH3COOH The oxidation of propanone involves the breaking of a carbon-carbon bond, leading to the formation of both formic acid and acetic acid.
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About Carboxylic Acids
Carboxylic acids are named and studied through the combined effects of the carbonyl and hydroxyl groups, their preparation, acidity and hydrogen bonding. Reactions include neutralisation, esterification, reduction and conversion into acid chlorides, anhydrides, esters and amides, with emphasis on how these derivatives interconvert.
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