Pressure versus density graph of an ideal gas is shown in figure. Which one of the options is the most suitable?
Correct answer: A. During the process AB work done by the gas is positive
- A. During the process AB work done by the gas is positive
- B. During the process AB work done by the gas is negative
- C. During the process BC internal energy of the gas is increasing
- D. None of these
Explanation
We know that,f(density)=nM/V [Mass=moles×Molar mass](Volume)so,V= nM/V (i)In process AB f is constant,Also, V→constant [By eq - (i)]so,ΔW=ΔPUAs ΔP=+ve [P is increasing from A to B]ΔW=Δ(PV)=VΔP+PΔV=VΔP toΔW=VΔP=+veIn process B-C, we havePM/RT=f⟹T=PM/RfAs P/f→constant, T=( P/f ) M/R→constantInternal energy (nCVT) will remain same.
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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