pH of a mixture which is 0.1 M CH3COOH and 0.05 M (CH3COO)2 Ba is [pKa of CH3COOH = 4.74]
Correct answer: A. 4.74
- A. 4.74
- B. 4.44
- C. 5.04
- D. 7.00
Explanation
Substituting the values into the Henderson-Hasselbalch equation, we get:pH = 4.74 + log(0.1 / 0.1)pH = 4.74 + log(1)pH = 4.74Therefore, the pH of the mixture is 4.74.
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About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
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