Oxidation state of 'Mn' in KMnO4, K2MnO4, MnO2 and MnSO4 is in the order:
Correct answer: C. +7, +6, +4, +2
- A. +7, +6, +2, +4
- B. +6, +7, +2, +4
- C. +7, +6, +4, +2
- D. +4, +6, +7, +2
Explanation
In KMnO4, we know that oxygen has a -2 oxidation state, and potassium has a +1 oxidation state. Let the oxidation state of manganese be x.Then, using the fact that the compound has a neutral charge:(+1) + x + 4(-2) = 0 x - 6 = 0 x = +6In K2MnO4, we have two potassium ions, each with a +1 oxidation state. Again, let the oxidation state of manganese be x.Then:2(+1) + x + 4(-2) = 02 + x - 8 = 0 x = +6In MnO2, we know that oxygen has a -2 oxidation state, so:2(-2) + x = 0x = +4In MnSO4, we know that oxygen has a -2 oxidation state, and sulfur has a +6 oxidation state. Let the oxidation state of manganese be x. Then: x + (-2)4 + (+6) = 0x - 8 + 6 = 0x = +2Thus, the correct order of increasing oxidation state of Mn is +7, +6, +4, +2, which corresponds to option (C).
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Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.
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Pick the correct statement:
The electronic configuration of Manganese (Mn) is