Moderate

Oxidation state of 'Mn' in KMnO4, K2MnO4, MnO2 and MnSO4 is in the order:

Correct answer: C. +7, +6, +4, +2

  • A. +7, +6, +2, +4
  • B. +6, +7, +2, +4
  • C. +7, +6, +4, +2
  • D. +4, +6, +7, +2

Explanation

In KMnO4, we know that oxygen has a -2 oxidation state, and potassium has a +1 oxidation state. Let the oxidation state of manganese be x.Then, using the fact that the compound has a neutral charge:(+1) + x + 4(-2) = 0 x - 6 = 0 x = +6In K2MnO4, we have two potassium ions, each with a +1 oxidation state. Again, let the oxidation state of manganese be x.Then:2(+1) + x + 4(-2) = 02 + x - 8 = 0 x = +6In MnO2, we know that oxygen has a -2 oxidation state, so:2(-2) + x = 0x = +4In MnSO4, we know that oxygen has a -2 oxidation state, and sulfur has a +6 oxidation state. Let the oxidation state of manganese be x. Then: x + (-2)4 + (+6) = 0x - 8 + 6 = 0x = +2Thus, the correct order of increasing oxidation state of Mn is +7, +6, +4, +2, which corresponds to option (C).

Last updated

About Transition Elements

Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.

Practise Transition Elements

531 free Transition Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Chemistry questions like this

Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions