Oxidation of secondary alcohol gives:

Explanation

Option D is correct.Oxidation of secondary alcohols gives ketones. The oxidation of secondary alcohols is a two-step process. In the first step, the alcohol is oxidized to an aldehyde. In the second step, the aldehyde is oxidized to a ketone.1.The first step of the oxidation of secondary alcohols is catalyzed by a strong oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4). In this step, the alcohol is oxidized to an aldehyde. The reaction can be represented by the following equation: RCH(OH)R' → RCH=O + H2O In this reaction, the alcohol is first protonated by the oxidizing agent. The protonated alcohol then undergoes a nucleophilic attack by the oxidizing agent. The oxidizing agent donates a pair of electrons to the carbonyl carbon of the alcohol, forming a new bond between the oxidizing agent and the alcohol. The carbonyl group is then hydrolyzed, resulting in the formation of an aldehyde. 2.The second step of the oxidation of secondary alcohols is also catalyzed by a strong oxidizing agent. In this step, the aldehyde is oxidized to a ketone. The reaction can be represented by the following equation: RCH=O + H2O2 → RCO-R' In this reaction, the aldehyde is first oxidized by hydrogen peroxide. The hydrogen peroxide donates a pair of electrons to the carbonyl carbon of the aldehyde, forming a new bond between the hydrogen peroxide and the aldehyde. This new bond is unstable and breaks, resulting in the formation of a ketone.