One end of the string of length 1.0 m is tied to a body of mass 0.5 kg. It is whirled in a vertical circle as shown in the figure below, the angular frequency of the body is 4 rads-1, what is the tension in the string when the body is at the topmost point A? Take g = 10 ms-2.
Correct answer: A. 3 N
- A. 3 N
- B. 13 N
- C. 15 N
- D. 18 N
Explanation
Tention = mω2r - mg (where m = mass, ω = angular velocity, r = radius) Tention = (0.5 x 42 x 1) - (0.5 x 10) Tention = (0.5 x 16) - 5 = 8 - 5 = 3N
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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