One end of cylindirical pipe has a radius of 1.5cm, water stream (density = 1.0 x 10^3 kg/m3) steadily out at 7.0m/s, the volume rate is:
Correct answer: A. 4.9 x 10^-3 m3/s
- A. 4.9 x 10^-3 m3/s
- B. 4.9 m3/s
- C. 7.0 m3/s
- D. 49 m3/s
Explanation
We are asked to find the volume rate of flow in this question. With the radius 1.5cm (0.015m) we can find the cross-sectional area of the cylinder with πr2 = π(0.015)2 = 0.0007The formula for volume rate is Q = vA, where Q= volume flow rate v = flow velocity (7.0m/s)A = cross sectional areaThus Q = 7 x 0.0007 = 0.0049 = 4.9 x 10-3
This question appeared on the ETEA MDCAT 2015 paper, which you can sit online with every answer explained.
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Fluid flow covers pressure, density, viscosity and the motion of liquids and gases through pipes or open channels. It includes the continuity equation, Bernoulli equation, streamline and turbulent flow, and the effects of changing area, height and speed. Viscosity and ideal fluid assumptions must not be confused with pressure effects.
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