On mixing 56 gm of CaO with 63 gm of HNO3, the amount of Ca(NO3)2 formed is ______________ gm?
Correct answer: A. 82
- A. 82
- B. 164
- C. 41
- D. 8.2
Explanation
The reaction is CaO + 2HNO3 → Ca(NO3)2 + H2O. One mole of HNO3 is supplied, so it forms 0.5 mol of Ca(NO3)2, or 0.5 × 164 = 82 g.
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