Number of moles present in 0.6 grams of Silica is? (Atomic mass Si=28 O=16)
Correct answer: A. 0.01 mole
- A. 0.01 mole
- B. 0.064 mole
- C. 0.044 mole
- D. 0.054 mole
Explanation
To calculate the number of moles in 0.6 grams of silica, we first need to calculate the molar mass of silica. The molar mass of a compound is the sum of the atomic masses of all the atoms in the compound.The molar mass of silica (SiO2) is:Molar mass of SiO2 = 28 g/mol (Si) + 2 * 16 g/mol (O) = 60 g/molNow that we know the molar mass of silica, we can calculate the number of moles in 0.6 grams of silica:Number of moles of SiO2 = 0.6 g / 60 g/mol = 0.01 molTherefore, there are 0.01 moles of silica in 0.6 grams of silica.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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