Moment of inertia of a thin rod of mass m, length l about a line passing through its center is:
Correct answer: E. 1/12 ml2
- A. ml2
- B. 1/2 ml2
- C. 1/3 ml2
- D. 2/5 ml2
- E. 1/12 ml2
Explanation
The moment of inertia of a thin rod of mass m and length l about an axis passing through its center of mass and perpendicular to its length is given by the formula:I = (1/12) ml2So, the correct option is E.
This question appeared on the NUMS 2019 (cancelled sitting) paper, which you can sit online with every answer explained.
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