Lowering in vapour pressure is the highest for:
Correct answer: D. 0.1 M BaCl2
- A. 0.2 M urea
- B. 0.1 M Glucose
- C. 0.1 M MgSO4
- D. 0.1 M BaCl2
Explanation
The higher the vanthoff factor, the greater the lowering of vapor pressure. The highest van der hoff factor is for BaCl2On dissociation, it gives 3 moles of ions (2 chloride and one barium). So the highest lowering of vapor pressure will be for BaCl2.
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About Colligative Properties
Colligative properties depend on the number of dissolved particles rather than their chemical identity. The topic covers relative lowering of vapour pressure, elevation of boiling point, depression of freezing point and osmotic pressure, including electrolyte dissociation, the van’t Hoff factor and molar-mass calculations.
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