Linear velocity or tangential velocity of any particle moving in a circular path of radlus 2m with angular velocity 8 rads-1 will be:
Correct answer: A. 16 ms-1
- A. 16 ms-1
- B. 4 ms-1
- C. 10 ms-1
- D. 6 ms-1
Explanation
Explanation: The linear velocity or tangential velocity (v) of a particle moving in a circular path is given by the product of the radius (r) and angular velocity (ω), i.e., v = rω Given r = 2m and ω = 8rads-1. Substituting the values, we get: v = rω = 2m × 8rads-1 = 16 m/s
This question appeared on the UHS MDCAT 2009 paper, which you can sit online with every answer explained.
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Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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