Lactose (molecular weight 342) is burnt completely according to the reaction: C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O. What weight of CO₂ would be formed when 1/12 mole of this compound is burnt?
Correct answer: C. 44 g
- A. 12 g
- B. 4.4 g
- C. 44 g
- D. 440 g
Explanation
According to the balanced equation, 1 mole of lactose produces 12 moles of CO₂. Therefore, 1/12 mole of lactose will produce (1/12) × 12 = 1 mole of CO₂. The mass is 1 mol × 44 g/mol (molar mass of CO₂) = 44 g.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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