In voltage divider bias, operating point is 3 V, 2 mA. If VCC = 9 V, RC = 2.2 kO, what is the value of RE ?
Correct answer: C. 800 O
- A. 2000 O
- B. 1400 O
- C. 800 O
- D. 1600 O
Explanation
Using VCC = VRC + VCE + VE, the emitter voltage is 9 − (2 mA)(2.2 kΩ) − 3 = 1.6 V. Thus RE = VE/IE = 1.6 V/2 mA = 800 Ω.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
Practise Electronics and Devices
758 free Electronics and Devices MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Electrical Engineering questions like this
Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electronics and Devices questions
The value of stability factor for a base resistor bias is________________?
If the temperature increases, the value of VCE_________________?
The stability factor of a collector feedback bias circuit is_______________ that of base resistor bias?
The disadvantage of voltage divider bias is that it has _________________?
For proper amplification by a transistor circuit, the operating point should be located at the_____________ of the d.c. load line?
The operating point is also called the _______________?