In the reaction represented by:zXA ⟶Z-2YA-4 ⟶ Z-2YA-4 ⟶Z-1KA-4The decay in the sequence are:
Correct answer: D. α,γ,β
- A. α,β,γ
- B. γ,α,β
- C. β,α,γ
- D. α,γ,β
Explanation
The equations can be written as:AZX → A-4Z-2Y + αA-4Z-2Y → A-4Z-2Y + βA-4Z-2Y → A-4Z-1K + γ
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