In the given figure, a force of 5 N is acting on an object towards East and then it moves towards North under the action of a 6 N force. The resultant force on the object is equal to
Correct answer: C. √61 N
- A. 32 N
- B. 7 N
- C. √61 N
- D. √11 N
Explanation
To find the resultant force, we need to add the forces vectorially. The 5 N force acting towards the East and the 6 N force acting towards the North are at right angles to each other. We can use the Pythagorean theorem to find the magnitude of the resultant force: Resultant force = √((5 N)² + (6 N)²) = √(25 N² + 36 N²) = √(61 N²) = √ 61 N.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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