In the differential voltage gain & the common mode voltage gain of a differential amplifier are 48db &2db respectively, then its common mode rejection ratio is__________?
Correct answer: C. 46dB
- A. 23dB
- B. 25dB
- C. 46dB
- D. 50dB
Explanation
The common-mode rejection ratio in decibels is the differential voltage gain minus the common-mode voltage gain: CMRR = 48 − 2 = 46 dB. Therefore option c is correct.
Last updated
Practise Electronics and Devices
758 free Electronics and Devices MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Electrical Engineering questions like this
Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1 db corresponds to_____________change in power level?
A 1,000 V power supply would use_____________ as a filter capacitor?
A 10 V power supply would use ____________ as filter capacitor?
A 2-transistor class B power amplifier is commonly called ______________ amplifier?
A 25eV electron has a speed of______________?