In the differential voltage gain & the common mode voltage gain of a differential amplifier are 48db &2db respectively, then its common mode rejection ratio is__________?

Correct answer: C. 46dB

  • A. 23dB
  • B. 25dB
  • C. 46dB
  • D. 50dB

Explanation

The common-mode rejection ratio in decibels is the differential voltage gain minus the common-mode voltage gain: CMRR = 48 − 2 = 46 dB. Therefore option c is correct.

Written and checked by , MS Computer ScienceLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

Practise Electronics and Devices

758 free Electronics and Devices MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Electrical Engineering questions like this

Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Electronics and Devices questions