In series resonant circuit, increasing inductance to its twice value and reducing capacitance to its half value__________?
Correct answer: D. will increase the selectivity of the circuit
- A. will change the maximum value of current at resonance
- B. will change the resonance frequency
- C. will change the impedance at resonance frequency
- D. will increase the selectivity of the circuit
Explanation
The resonance frequency is unchanged because LC remains constant when L is doubled and C is halved. However, the selectivity increases because Q = (1/R)√(L/C), and the L/C ratio becomes four times larger.
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