In hybridization, increased 's' character will make the bond length:
Correct answer: B. Shorter
- A. Same
- B. Shorter
- C. None of these
- D. Greater
Explanation
Greater the s - character, the closer the orbitals are to the nucleus and hence form stronger and shorter bonds.s −character in different hybridization states are: sp3 (25%), sp2 (33%), sp (50%)Bond length: alkanes (sp3) > alkenes (sp2) > alkynes (sp)The table presented below substantiates the claim by using actual data. It shows how alkanes have a greater bond length, followed by alkenes, and alkynes in the last place.
Last updated
About Chemical Bonding
Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.
Practise Chemical Bonding
964 free Chemical Bonding MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
50% inversion of configuration and 50% retention of configuration observed is characteristics of mechanism:
A bonding electron pair is attracted by of atoms?
A Cl₂ molecule is formed by the overlap of:
A co-ordinate covalent bond is present in:
A covalent bond formed by the parallel overlap of p-orbitals is a weaker bond called: