In Balmer series the shortest wavelength radiations have wavelength equal to:
Correct answer: C. 4/RH
- A. RH/4
- B. RH/9
- C. 4/RH
- D. 9RH
Explanation
In the Balmer series, the shortest wavelength comes from the limiting transition (infinity to 2 ). Using the Rydberg formula lambda=4/RH. So the shortest wavelength in the Balmer series is 4/RH.
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