In an artificial satellite, an object appears to be weightless when its rotational acceleration 'α' isequal to
Correct answer: C. g.
- A. g / 4.
- B. g / 2.
- C. g.
- D. 2 g.
Explanation
In an artificial satellite, an object appears weightless when it is in a state of continuous free fall towards Earth. This happens because the satellite and everything inside it, including the object, are accelerating towards the Earth at the same rate as the gravitational pull, g. Therefore, the correct rotational acceleration, α, that results in weightlessness is equal to g. Other values like g/4, g/2, or 2g do not satisfy the condition for weightlessness, as they do not match the gravitational acceleration.
Last updated
Related questions
A body of mass m is attached to a spring balance which is attached to the ceiling of an elevator. If the elevator moves up with a certain acceleration, the apparent weight of the body will be
A man of weight \( w \) is standing on an elevator which is ascending with an acceleration \( a \). The apparent weight of the man is
A monkey sits on the pan of a spring scale. The reading of the spring scale will be maximum when the elevator is kept in an elevator
If the weight of a man is 100N and he is sitting in an elevator. Which is moving down with an acceleration of 9.8 m/s², then the apparent weight of the mass will be
Once the space shuttle is in orbit at a radius R from earth's center, what force does the seat exert on the astronaut?