In a titration experiment, 25.0 mL of 0.1 M NaOH is required to neutralize 20.0 mL of HCl solution. What is the molarity of the HCl solution?
Correct answer: B. 0.125 M
- A. 0.08 M
- B. 0.125 M
- C. 0.2 M
- D. 0.25 M
Explanation
For neutralization, moles of NaOH = moles of HCI. Moles of NaOH = 0.1 mol/L x 0.025 L = 0.0025 mol. Molarity of HCI=moles/volume=0.0025/0.020= 0.125 M.
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