In a spectrophotometric analysis, a solution absorbs 0.602 units at 450 nm. If the path length is 1.0 cm and the molar absorptivity is 1.5 × 10³ L/mol•cm, what is the concentration of the solution?
Correct answer: A. 4.01 × 10⁻⁴ M
- A. 4.01 × 10⁻⁴ M
- B. 2.01 × 10⁻³ M
- C. 4.01 × 10⁻³ M
- D. 9.03 × 10⁻⁴ M
Explanation
Beer-Lambert Law: A = ε × c × l. Concentration c = A/(ε × l) = 0.602/(1.5 × 10³ × 1.0) = 4.01 × 10⁻⁴ M.
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About Experimental Techniques in Chemistry
Separation methods are selected according to differences in solubility, particle size, volatility and sublimation behaviour. Filtration and crystallisation separate insoluble or dissolved solids, sublimation isolates suitable volatile solids, distillation separates liquids by boiling point, and solvent extraction transfers a substance between immiscible solvents.
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