In a single stage extraction process, 10 kg of pure solvent S (containing no solute A) is mixed with 30 kg of feed F containing A at a mass fraction xf = 0.2. The mixture splits into an extract phase E and a raffinate phase R containing A at xB = 0.5 and xR = 0.05 respectively. The total mass of the extract phase is (in Kg) ?
Correct answer: B. 8.89
- A. 6.89
- B. 8.89
- C. 10
- D. 8.25
Explanation
Overall balances give E + R = 40 and the solute balance gives 0.5E + 0.05R = 6. Substitution yields 0.45E = 4, so E = 8.89 kg.
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