In a simple electrical circuit the current in a resistor is measured as (2.50 +_ 0.05) mA. The resistor is marked as having a value of 4.7 _+2%. If these value where used to calculate the power dissipated in the percentage uncertainty in the value obtained ?
Correct answer: C. 6%
- A. 2%
- B. 4%
- C. 6%
- D. 8%
Explanation
First we find out the % uncertainty in current (0.05)/2.5 x 100 = 2%. Then we note the formula of power dissipated is 12 x R so the = percentage uncertainty has to be added i.e (2+2)+2=6%As it is numerical, it can have only one possible answer.
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