In a reversible adiabatic process, the entropy of the system:
Correct answer: C. Remains constant
- A. Increases
- B. Decreases
- C. Remains constant
- D. Becomes zero
Explanation
In a reversible adiabatic process, no heat is exchanged (Q = 0), so the entropy change (ΔS = Q/T) is zero, and the system's entropy remains constant.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Thermal Equilibrium and Heat
Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Thermal Equilibrium and Heat questions
A heat engine operates with a hot reservoir at 500 K and a cold reservoir at 300 K. If 1000 J of heat is absorbed, the maximum work output is:
The entropy of a system increases when:
The latent heat of fusion of ice at 0°C is 334 kJ/kg. The entropy change when 1 kg of ice melts is:
The heat required to convert 2 kg of water at 100°C to steam at 100°C (latent heat of vaporization = 2260 kJ/kg) is:
Which of the following curve is an isotherm?
Which process is shown in the graph between pressure and volume given below?