Asked in MDCAT Test Series 5 — Waves and Thermodynamics (7 March 2025) 2025

In a process the density of gas remains constant. If the temperature is doubled, then the change in the pressure will be:

Correct answer: A. 100% increase

  • A. 100% increase
  • B. 200% increase
  • C. 50% decrease
  • D. 25% decrease

Explanation

In an ideal gas where the density remains constant, the relationship between pressure (P), volume (V), and temperature (T) is given by the ideal gas law: PV = nRT. Since density (ρ) is constant, we can express it as ρ = PM/RT. If the temperature (T) is doubled and density remains constant, the pressure must also double to maintain the equation. Therefore, if the initial pressure is P1, the new pressure P2 will be 2P1, indicating a 100% increase in pressure. The other options are incorrect because they do not reflect the proper relationship between pressure and temperature under these conditions.

Written and checked by , contributorLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About Thermal Equilibrium and Heat

Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.

Practise Thermodynamics

714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Physics questions like this

Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More Thermal Equilibrium and Heat questions