In a parallel plate capacitor of capacitance C, a metal sheet is inserted between the plates, parallel to them. The thickness of the sheet is half of the separation between the plates. The capacitance now becomes:
Correct answer: B. 2C
- A. 4C
- B. 2C
- C. C/2
- D. C/4
Explanation
Before the metal sheet is inserted, C = εo A/d After the sheet is inserted, the system is equivalent to two capacitors in series, each of capacitance: C'= ε0A/d/4 = 4C The equivalent capacity is now 2C.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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