In a npn transistor, the current lE that flows in the emitter circuit is:
Correct answer: A. Ie = Ic + Ib
- A. Ie = Ic + Ib
- B. Ie = Ic - Ib
- C. Ie = Ib / Ic
- D. Ie = Ic * Ib
Explanation
This is the correct relationship between the emitter current (Ie), collector current (Ic), and base current (Ib) in an NPN transistor. The emitter current is equal to the sum of the collector current and the base current. This is because the majority of the charge carriers (electrons) entering the emitter region either flow to the collector or recombine with holes in the base region.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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