In a liquid-liquid heat exchanger, for the same process temperature, the ratio of the LMTD in parallel flow to the LMTD in counter flow is always__________________?
Correct answer: A. < 1
- A. < 1
- B. > 1
- C. 1
- D. ∞
Explanation
Counter-current flow maintains a larger average temperature-driving force than parallel flow for the same terminal temperatures, so its LMTD is greater. Therefore, the parallel-flow LMTD divided by the counter-flow LMTD is less than 1.
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