In a full-wave rectifier using two ideal diodes,Vdc & Vm are the dc & peak values of the voltage respectively across a resistive load. If PIV is the peak inverse voltage of the diode, then the appropriate relationships for this rectifier is____________?
Correct answer: B. Vdc = 2Vm/π, PIV=2vm
- A. Vdc = Vm/π, PIV=2Vm
- B. Vdc = 2Vm/π, PIV=2vm
- C. Vdc = 2Vm/π, PIV=Vm
- D. Vdc = Vm/π, PIV=Vm
Explanation
For a center-tapped full-wave rectifier, the average load voltage is 2Vm/π, and the nonconducting diode must withstand twice the peak secondary-half voltage, so PIV = 2Vm. These values correspond to option b.
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