In a full-wave rectifier using two ideal diodes,Vdc & Vm are the dc & peak values of the voltage respectively across a resistive load. If PIV is the peak inverse voltage of the diode, then the appropriate relationships for this rectifier is____________?
Correct answer: B. Vdc = 2Vm/π, PIV=2vm
- A. Vdc = Vm/π, PIV=2Vm
- B. Vdc = 2Vm/π, PIV=2vm
- C. Vdc = 2Vm/π, PIV=Vm
- D. Vdc = Vm/π, PIV=Vm
Explanation
For a center-tapped full-wave rectifier, the average load voltage is 2Vm/π, and the nonconducting diode must withstand twice the peak secondary-half voltage, so PIV = 2Vm. These values correspond to option b.
Last updated
Practise Electronics and Devices
758 free Electronics and Devices MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Electrical Engineering questions like this
Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1 db corresponds to_____________change in power level?
A 1,000 V power supply would use_____________ as a filter capacitor?
A 10 V power supply would use ____________ as filter capacitor?
A 2-transistor class B power amplifier is commonly called ______________ amplifier?
A 25eV electron has a speed of______________?