In a dihybrid cross, how many homozygous offsprings can be produced?
Correct answer: A. 4
- A. 4
- B. 3
- C. 2
- D. 9
Explanation
In a dihybrid cross, two traits are considered, each with two alleles. The result is a 4x4 Punnett square with 16 possible genotypes. Homozygous refers to having two identical alleles for a trait. The four homozygous combinations are: RRYY, rrYY, RRyy, and rryy. These combinations reflect both traits being homozygous, either dominant or recessive.Options B, C, and D are incorrect because they do not represent the correct number of homozygous offspring that can result from a dihybrid cross. Specifically, three and two are too few, while nine refers to the count of genotypes rather than homozygous ones.
This question appeared on the ETEA MDCAT 2012 paper, which you can sit online with every answer explained.
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About Mendel's Laws of Inheritance
Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.
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