In a car dealership, all of the vehicles are either a sedan or a SUV. If 36 sedans are sold and 36 SUVs are added, there will be an equal number of sedans and SUVs. If 8 SUVs are sold and 8 sedans are added, there will be twice as many sedans as SUVs. How many sedans were at the dealership before any vehicle was sold?

Explanation

Let number of sedans originally = SLet number of SUVs originally = UIf 36 sedans are sold and 36 SUVs are added, there will be an equal number of sedans and SUVs.S - 36 = U + 36S - U = 72 eq-(1)If 8 SUVs are sold and 8 sedans are added, there will be twice as many sedans as SUVs.S+8=2(U−8)S+8=2U−16S=2U−24 eq-(2)From (1):S=U+72Substitute into (2):U+72=2U−2472+24=2U−UU=96Now substitute back:S=U+72=96+72=168Hence the correct answer is 168. Options A, B, and C are incorrect as they do not align with the calculated original number of sedans.