If we drop an object, it's initial velocity is zero. How far will it fall in time 't'?
Correct answer: B. 4.9 t^2
- A. 9.8 t^2
- B. 4.9 t^2
- C. 0.49 t^2
- D. 98 t^2
Explanation
Use the kinematics, straight line motion formula : s= u +½ at^2 s= 0 + ½ x 9.8x t^2 s= 4.9t^2
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