If we cross round yellow seeded plant with green wrinkled seeded plants, what will be phenotypic ratio at F2 generation?
Correct answer: A. 9:3:3:1
- A. 9:3:3:1
- B. 9:4:3:2
- C. 3:9:3:1
- D. 8:3:3:2
- E. 9:1:3:3
Explanation
This question is based on Mendelian genetics and the law of segregation. The round and yellow seed traits are dominant, while the wrinkled and green seed traits are recessive. When a homozygous round yellow seeded plant (RRYY) is crossed with a homozygous green wrinkled seeded plant (rryy), the F1 generation will all be heterozygous round yellow seeded (RrYy). When these F1 plants are crossed with each other, the resulting phenotypic ratio of the F2 generation will be 9 round yellow : 3 round green : 3 wrinkled yellow: 1 wrinkled green.
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About Inheritance
Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
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