If Vrms be the root mean square value of emf then its peak to peak value is given by:
Correct answer: D. 2√2 Vrms
- A. Vrms/√2
- B. √2Vrms
- C. 2/√2 Vrms
- D. 2√2 Vrms
Explanation
The correct answer is 2√2 Vrms. In an AC circuit, the RMS value is a measure of the effective value of an alternating current or voltage. The peak value (Vpeak) can be calculated from the RMS value using the formula Vpeak = √2 Vrms. To find the peak-to-peak value (Vpp), we multiply the peak value by 2, leading to the final formula Vpp = 2Vpeak = 2√2 Vrms.Option A is incorrect because it suggests dividing the RMS value by √2, which is the wrong operation for finding peak-to-peak. Option B is misleading as well, since while it correctly states that the peak value relates to RMS by √2, it fails to account for the factor of 2 needed for peak-to-peak. Option C is incorrect as it presents an irrelevant fraction that does not align with the required calculation.
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