If Vrms be the root mean square value of emf then its peak to peak value is given by:
Correct answer: D. 2√2 Vrms
- A. Vrms/√2
- B. √2Vrms
- C. 2/√2 Vrms
- D. 2√2 Vrms
Explanation
The correct answer is 2√2 Vrms. In an AC circuit, the RMS value is a measure of the effective value of an alternating current or voltage. The peak value (Vpeak) can be calculated from the RMS value using the formula Vpeak = √2 Vrms. To find the peak-to-peak value (Vpp), we multiply the peak value by 2, leading to the final formula Vpp = 2Vpeak = 2√2 Vrms.Option A is incorrect because it suggests dividing the RMS value by √2, which is the wrong operation for finding peak-to-peak. Option B is misleading as well, since while it correctly states that the peak value relates to RMS by √2, it fails to account for the factor of 2 needed for peak-to-peak. Option C is incorrect as it presents an irrelevant fraction that does not align with the required calculation.
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Alternating current varies periodically, so phase relationships become essential when current passes through a resistor, capacitor or inductor. The chapter distinguishes resistance from capacitive and inductive reactance, explains phase lead and lag, and connects changing electric and magnetic fields with the production and properties of electromagnetic waves.
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