If two capacitors of 10 µF each are connected in series combination, then their equivalentcapacitance will be

Correct answer: C. 5 µF.

  • A. 0 µF.
  • B. 1 µF.
  • C. 5 µF.
  • D. 20 µF.

Explanation

When two capacitors, each with a capacitance of 10 µF, are connected in series, the formula for their equivalent capacitance is 1/C_eq = 1/C_1 + 1/C_2. Substituting the given values, we have 1/C_eq = 1/10 + 1/10 = 2/10, which simplifies to 1/C_eq = 1/5. Therefore, C_eq = 5 µF. This is less than the capacitance of each individual capacitor, which is a characteristic of capacitors in series. The other options are incorrect because they either misapply the series formula or confuse the series and parallel configurations.

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Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.

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